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TS4962M 데이터시트(PDF) 22 Page - STMicroelectronics

부품명 TS4962M
상세설명  3W Filter - free Class D Audio Power Amplifier
PDF  32 Pages
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제조업체  STMICROELECTRONICS [STMicroelectronics]
홈페이지  http://www.st.com
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TS4962M 데이터시트(HTML) 22 Page - STMicroelectronics

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Application Information
TS4962M
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5.3
Common mode feedback loop limitations
As explained previously, the common mode feedback loop allows the output DC bias voltage to
be averaged at VCC/2 for any DC common mode bias input voltage.
However, due to Vicm limitation in the input stage (see Table 2: Operating conditions on page 2),
the common mode feedback loop can ensure its role only within a defined range. This range
depends upon the values of VCC and Rin (Av). To have a good estimation of the Vicm value, we
can apply this formula (no tolerance on Rin):
with
and the result of the calculation must be in the range:
Due to the +/-9% tolerance on the 150k
Ω resistor, it’s also important to check Vicm in these
conditions:
If the result of Vicm calculation is not in the previous range, input coupling capacitors must be
used (with VCC from 2.4V to 2.5V, input coupling capacitors are mandatory).
For example:
With VCC =3V, Rin = 150k and VIC = 2.5V, we found Vicm = 2V typically and this is lower than
3V - 0.8V = 2.2V. With 136.5k
Ω we found 1.97V and with 163.5kΩ we have 2.02V. So, no input
coupling capacitors are required.
5.4
Low frequency response
If a low frequency bandwidth limitation is requested, it’s possible to use input coupling
capacitors.
In the low frequency region, Cin (input coupling capacitor) starts to have an effect. Cin forms,
with Rin, a first order high-pass filter with a -3dB cut-off frequency:
So, for a desired cut-off frequency we can calculate Cin,
with Rin in W and FCL in Hz.
V
icm
V
CC
R
in
×
2V
IC
×
150k
Ω
×
+
2R
in
150k
Ω
+
()
×
----------------------------------------------------------------------------
(V)
=
V
IC
In
+
In
-
+
2
---------------------
(V)
=
0.5V
V
icm
V
CC
0.8V
–
≤≤
V
CC
R
in
×
2V
IC
×
136.5k
Ω
×
+
2R
in
136.5k
Ω
+
()
×
---------------------------------------------------------------------------------
V
icm
V
CC
R
in
×
2V
IC
×
163.5k
Ω
×
+
2R
in
163.5k
Ω
+
()
×
---------------------------------------------------------------------------------
≤≤
F
CL
1
2
π R
in
×
C
in
×
------------------------------------
(Hz)
=
C
in
1
2
π R
in
×
F
CL
×
--------------------------------------
(F)
=



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