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TDA8433 데이터시트(PDF) 18 Page - NXP Semiconductors |
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TDA8433 데이터시트(HTML) 18 Page - NXP Semiconductors |
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18 / 25 page ![]() August 1991 18 Philips Semiconductors Product specification Deflection processor for computer controlled TV receivers TDA8433 APPLICATION INFORMATION The formulae from which the typical vertical drive and typical E-W drive waveforms are generated are given in the following sub-paragraphs. For this purpose a typical application diagram for the vertical drive stage is assumed to be as illustrated in Fig.7. Pin 20 is the vertical drive output which drives an inverting power amplifier. The feedback network, R1 to R4 and C1 and C2, has two functions; • To transfer the voltage on the feedback pin (pin 21) to a voltage across the feedback resistor R1 • To stabilize the voltage across C1 at a fixed value. For this typical application the formula for the vertical scan waveform refers to the voltage at pin 21. The formula for the E-W drive waveform refers to the voltage at pin 19. All DAC variables that control the vertical and E-W drive waveforms are normalized. Each DAC is defined as having a control range between 0 and 1. The 0 corresponds to a register value of HEX00 and the 1 to a maximum value of HEX1F (for a 5-bit DAC) or HEX3F (for a 6-bit DAC). Table 4 DAC variables Further definitions VSAW = Instantaneous sawtooth voltage (pin 22) normally; 0 < Vsaw < 7.1 V; VCC = supply voltage applied to pin 12. VEHT = EHT compensation voltage applied to pin 1, normally between 1/2 VCC and 1/7 VCC. VOFF = Internal offset voltage. Vint = Internal reference voltage of 7.1 V (also on pin 4) If the Trapezium function (T) compensates for the internal offset voltage then the actual formula for Z will simplify to: Z = −1 + 2Vsaw/Vint Since 0 V < VSAW < 7.1 V, this is simply a negative going sawtooth and it follows that: −1 < Z < 1. a: Picture height 0 < a < 1 64 steps (6 bits) y: V-linearity 0 < y < 1 64 steps (6 bits) s: V-S correction 0 < s < 1 64 steps (6 bits) d: V-shift 0 < d < 1 64 steps (6 bits) v: V-compensation 0 < v < 1 32 steps (5 bits) w: Picture width 0 < w < 1 64 steps (6 bits) p: E-W parabola 0 < p < 1 64 steps (6 bits) c: E-W corner 0 < c < 1 64 steps (6 bits) t: Trapezium 0 < t < 1 64 steps (6 bits) h: H-compensation 0 < h < 1 32 steps (5 bits) A = 0.80 (a + 2)/3 P = 0.55 p Y = 0.17 y C = 0.38 c S = 0.42 s T = 0.32 (1 + 2t) volts D = 2.4 − 0.7 d volts E = (VCC / 2 − VEHT) / 42 W = 0.16 w Z = −1 + 2 x (V saw − T) Vint |
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