| 전자부품 데이터시트 검색엔진 |
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4LS10K 데이터시트(PDF) 51 Page - OSRAM GmbH |
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4LS10K 데이터시트(HTML) 51 Page - OSRAM GmbH |
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51 / 115 page ![]() Document Feedback 4LS Functional Description Datasheet • PUBLIC DS000542 • v3-01 • 2022-Nov-17 114 │ 50 8-Bit mode @ 80 MHz Below described is an example to calculate the maximum line rate for 8-bit mode, for the below configuration. The region of interested is based on Figure 71. ● Output mode: 8-bit ● Readout mode: 1-To-1 LVDS ● ADC response stabilization OFF ● Auto-start AD OFF ● Auto-start readout OFF ● End of Range = 0x3F For full resolution, it was verified that the minimum Readout Time is much higher than the ADC time, therefore the maximum line rate was defined by the Readout Time. When performing a ROI in sensor, the goal is to calculate how much the Readout Time can be decreased to achieve the highest line rate possible. Taking in consideration Equation 4, the MTA and maximum line rate as shown below: Figure 73: 8-Bit Timing Clocks with ROI On for Readout Mode 1-To-1 – MTA Calculation Parameters Clocks ADC Time 280 SAMPLE 40 START_AD 2 TBTW_START_AD&RST_RAMP 1 TBTW_SAMPLE&START_AD 12 DTI 112 MTA 335 => 238.8 kLines/s Max Integration Time(1) 223 => 2787.5 ns (1) To use the sensor at the maximum line, this is the maximum integration time possible. When it comes to the minimum integration time, in theory, it is possible to use a lower integration time, but it was not tested on this configuration. From an application perspective, using a lower integration time, does not bring significant advantages, once the line rate cannot be higher and the system would need to increase the illumination power. Now the Readout Time needs to be calculated in order to achieve the respective line rate and guarantee the minimum LVAL Low Period. ● Start Region of Interest Register Segment A = 0x54 = 84d ● Start Region of Interest Register Segment B = 0x00 ● End Region of interest Register Segment A = 0xA0 = 160d ● End Region of Interest Register Segment B = 0x4C = 76d ������������������������ = ((160 − 84) + 1) × (4 × 1)) = 308 ������������������������������������ ������������������������������������������ ������������������������ = 308 + 26 = 334 ������������������������������������ |
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