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PIC18F258-E/LSQTP 데이터시트(PDF) 319 Page - Microchip Technology

부품명 PIC18F258-E/LSQTP
상세설명  28/40-Pin High-Performance, Enhanced Flash Microcontrollers with CAN Module
PDF  402 Pages
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제조업체  MICROCHIP [Microchip Technology]
홈페이지  http://www.microchip.com
Logo MICROCHIP - Microchip Technology

PIC18F258-E/LSQTP 데이터시트(HTML) 319 Page - Microchip Technology

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© 2006 Microchip Technology Inc.
DS41159E-page 317
PIC18FXX8
SUBLW
Subtract W from Literal
Syntax:
[
label ]SUBLW k
Operands:
0
≤ k ≤ 255
Operation:
k – (W)
→ W
Status Affected:
N, OV, C, DC, Z
Encoding:
0000
1000
kkkk
kkkk
Description:
W is subtracted from the eight-bit
literal ‘k’. The result is placed in W.
Words:
1
Cycles:
1
Q Cycle Activity:
Q1
Q2
Q3
Q4
Decode
Read
literal ‘k’
Process
Data
Write to W
Example 1:
SUBLW
0x02
Before Instruction
W=
1
C=
?
After Instruction
W=
1
C
=
1
; result is positive
Z=
0
N=
0
Example 2:
SUBLW
0x02
Before Instruction
W=
2
C=
?
After Instruction
W=
0
C
=
1
; result is zero
Z=
1
N=
0
Example 3:
SUBLW
0x02
Before Instruction
W=
3
C=
?
After Instruction
W
=
FF
; (2’s complement)
C
=
0
; result is negative
Z=
0
N=
1
SUBWF
Subtract W from f
Syntax:
[
label ]
SUBWF
f [,d [,a]]
Operands:
0
≤ f ≤ 255
d
∈ [0,1]
a
∈ [0,1]
Operation:
(f) – (W)
→ dest
Status Affected:
N, OV, C, DC, Z
Encoding:
0101
11da
ffff
ffff
Description:
Subtract W from register ‘f’ (2’s
complement method). If ‘d’ is ‘0’, the
result is stored in W. If ‘d’ is ‘1’, the
result is stored back in register ‘f’
(default). If ‘a’ is ‘0’, the Access Bank
will be selected, overriding the BSR
value. If ‘a’ is ‘1’, then the bank will be
selected as per the BSR value
(default).
Words:
1
Cycles:
1
Q Cycle Activity:
Q1
Q2
Q3
Q4
Decode
Read
register ‘f’
Process
Data
Write to
destination
Example 1:
SUBWF REG
Before Instruction
REG
=
3
W=
2
C=
?
After Instruction
REG
=
1
W=
2
C
=
1
; result is positive
Z=
0
N=
0
Example 2:
SUBWF REG, W
Before Instruction
REG
=
2
W=
2
C=
?
After Instruction
REG
=
2
W=
0
C
=
1
; result is zero
Z=
1
N=
0
Example 3:
SUBWF REG
Before Instruction
REG
=
0x01
W
=
0x02
C=
?
After Instruction
REG
=
0xFFh ;(2’s complement)
W
=
0x02
C
=
0x00
; result is negative
Z
=
0x00
N
=
0x01



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