AN2986 datasheet(8/18 Pages) STMICROELECTRONICS

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Gate resistor choice

AN2986

8/18

Doc ID 15727 Rev 1

VGT (0 °C) = 1 + 0.05 V,

VOLmax [ 25 °C, IGT (0 °C)] = 0.55 V

RG is then given by:

Equation 2

The standard value of the resistor is 180

Ω which is also sufficient for accuracy of ±5%.

Example 2: STM32103RB + Z0103 for 3.3 V ±5%

Specified values:

IGT (25 °C)= 3 mA, VDD = 3.3 V, VGT (25 °C) = 1.3 V

Calculated values: IGT (0 °C) = 1.5 x IGT (25 °C) = 4.5 mA,

VDDmin = 0.95 x 3.3 V = 3.13 V,

VGT (0 °C) = 1.3 + 0.05 V,

VOLmax (IG = 8 mA) = 0.4 V

RG is then given by:

Equation 3

The standard value of the resistor is 300

Ω. The value 270 Ω is sufficient for accuracy of

±5%.

Please remember that we are focusing on Q2/Q3 operation (refer to AN2703 for quadrant

definition). For Q1/Q4 operation, "VDDmin – VOLmax" in Equation 1 has to be replaced by

VOHmin. Usually VOHmin is reached for minimum VDD.

Also, if a positive power supply is used (i.e. the device works in Q1/Q4 quadrants), the

required gate current is higher for Q4 operations (5 mA instead of 3 mA for other quadrants

for Z0103), and the gate resistor has to be lower than 182

Ω (RG < 182 Ω for VOHmin =

VDDmin –0.4 V).

4.5

1.05

–

0.55

–

0.015

1.01

-------------------------------------------

192

3.13

1.35

–

0.4

–

0.0045

1.01

-------------------------------------------

303

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