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HCS08 데이터시트(PDF) 137 Page - NXP Semiconductors |
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HCS08 데이터시트(HTML) 137 Page - NXP Semiconductors |
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137 / 316 page ![]() Analog-to-Digital Converter (S08ADCV1) MC9S08SG8 MCU Series Data Sheet, Rev. 8 Freescale Semiconductor 137 result of the conversion is transferred to ADCRH and ADCRL upon completion of the conversion algorithm. If the bus frequency is less than the fADCK frequency, precise sample time for continuous conversions cannot be guaranteed when short sample is enabled (ADLSMP=0). If the bus frequency is less than 1/11th of the fADCK frequency, precise sample time for continuous conversions cannot be guaranteed when long sample is enabled (ADLSMP=1). The maximum total conversion time for different conditions is summarized in Table 9-12. The maximum total conversion time is determined by the clock source chosen and the divide ratio selected. The clock source is selectable by the ADICLK bits, and the divide ratio is specified by the ADIV bits. For example, in 10-bit mode, with the bus clock selected as the input clock source, the input clock divide-by-1 ratio selected, and a bus frequency of 8 MHz, then the conversion time for a single conversion is: NOTE The ADCK frequency must be between fADCK minimum and fADCK maximum to meet ADC specifications. Table 9-12. Total Conversion Time vs. Control Conditions Conversion Type ADICLK ADLSMP Max Total Conversion Time Single or first continuous 8-bit 0x, 10 0 20 ADCK cycles + 5 bus clock cycles Single or first continuous 10-bit 0x, 10 0 23 ADCK cycles + 5 bus clock cycles Single or first continuous 8-bit 0x, 10 1 40 ADCK cycles + 5 bus clock cycles Single or first continuous 10-bit 0x, 10 1 43 ADCK cycles + 5 bus clock cycles Single or first continuous 8-bit 11 0 5 s + 20 ADCK + 5 bus clock cycles Single or first continuous 10-bit 11 0 5 s + 23 ADCK + 5 bus clock cycles Single or first continuous 8-bit 11 1 5 s + 40 ADCK + 5 bus clock cycles Single or first continuous 10-bit 11 1 5 s + 43 ADCK + 5 bus clock cycles Subsequent continuous 8-bit; fBUS fADCK xx 0 17 ADCK cycles Subsequent continuous 10-bit; fBUS fADCK xx 0 20 ADCK cycles Subsequent continuous 8-bit; fBUS fADCK/11 xx 1 37 ADCK cycles Subsequent continuous 10-bit; fBUS fADCK/11 xx 1 40 ADCK cycles 23 ADCK cyc Conversion time = 8 MHz/1 Number of bus cycles = 3.5 s x 8 MHz = 28 cycles 5 bus cyc 8 MHz + = 3.5 s |
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